Solve the system of equations by the substitution method.
-$2 y = x + 8$
$2 x + 4 y = 0$
A) $\{ ( - 4,2 ) \}$
B) $\{ ( 2 , - 4 ) \}$
C) $\{ ( - 4 , - 2 ) \}$
D) $\{ ( 4,1 ) \}$

Question

Quizplus · Accepted Answer

First, solve the first equation for $x$: $x = 2y - 8$. Substitute $x$ in the second equation: $2(2y - 8) + 4y = 0$, which simplifies to $8y - 16 = 0$, leading to $y = 2$. Substitute $y = 2$ back into $x = 2y - 8$ to find $x = -4$. Thus, the solution is $(-4, 2)$.

Solve the System of Equations by the Substitution Method 2y=x+82 y = x + 82y=x+8

Solve the System of Equations by the Substitution Method $2 y = x + 8$