Use Cramer's rule to solve the system.
-$$\begin{array} { l }
2 x + 2 y = 10 \
2 x - 2 y = 6
\end{array}$$
A) $\{ ( 4,1 ) \}$
B) $\{ ( 1,4 ) \}$
C) $\{ ( - 1,4 ) \}$
D) $\{ ( - 4 , - 1 ) \}$

Question

Use Cramer's rule to solve the system.
-$$\begin{array} { l } 
2 x + 2 y = 10 \
2 x - 2 y = 6
\end{array}$$
A) $\{ ( 4,1 ) \}$
B) $\{ ( 1,4 ) \}$
C) $\{ ( - 1,4 ) \}$
D) $\{ ( - 4 , - 1 ) \}$

Quizplus · Accepted Answer

Cramer's rule involves calculating determinants. The determinant of the coefficient matrix is $2(-2) - 2(2) = -8$. For $x$, replace the first column with the constants to get a determinant of $10(-2) - 6(2) = -32$, so $x = -32 / -8 = 4$. For $y$, replace the second column, getting $2(6) - 2(10) = -8$, so $y = -8 / -8 = 1$. Thus, the solution is $(4, 1)$.

Use Cramer's Rule to Solve the System 2x+2y=102x−2y=6\begin{array} { l } 2 x + 2 y = 10 \\2 x - 2 y = 6\end{array}2x+2y=102x−2y=6​

Use Cramer's Rule to Solve the System $\begin{array} { l } 2 x + 2 y = 10 \\2 x - 2 y = 6\end{array}$