Solve the matrix equation for X.
-Let $A = \left[ \begin{array} { r r } 1 & 4 \ 0 & - 2 \ 6 & - 6 \end{array} \right]$ and $B = \left[ \begin{array} { r r } 8 & - 6 \ - 1 & 4 \ 0 & 5 \end{array} \right] ; \quad B - X = 3 A$
A)
$X = \left[ \begin{array} { r r } 5 & - 18 \ - 1 & 10 \ - 18 & 23 \end{array} \right]$
B)
$X = \left[ \begin{array} { r r } 11 & 6 \ 1 & - 2 \ 18 & - 13 \end{array} \right]$
C)
$X = \left[ \begin{array} { r r } 5 & - 18 \ 1 & 10 \ - 18 & 23 \end{array} \right]$
D)
$X = \left[ \begin{array} { r r } 11 & 6 \ 1 & - 2 \ 6 & - 13 \end{array} \right]$

Question

Quizplus · Accepted Answer

Given $B - X = 3A$, we solve for $X$ as $X = B - 3A$. Calculating $3A$ gives $\left[ \begin{array} { r r } 3 & 12 \ 0 & -6 \ 18 & -18 \end{array} \right]$. Subtracting this from $B$ yields $X = \left[ \begin{array} { r r } 5 & -18 \ -1 & 10 \ -18 & 23 \end{array} \right]$.

Solve the Matrix Equation for X A=[140−26−6]A = \left[ \begin{array} { r r } 1 & 4 \\ 0 & - 2 \\ 6 & - 6 \end{array} \right]A=​106​4−2−6​​

Solve the Matrix Equation for X $A = \left[ \begin{array} { r r } 1 & 4 \\ 0 & - 2 \\ 6 & - 6 \end{array} \right]$