Write Terms of an Arithmetic Sequence
-$$a _ { n } = a _ { n - 1} - \frac { 1 } { 3 } ; a _ { 1 } = - \frac { 1 } { 2 }$$
A) $- \frac { 1 } { 2 } , - \frac { 5 } { 6 } , - \frac { 7 } { 6 } , - \frac { 3 } { 2 } , - \frac { 11 } { 6 }$
B) $- \frac { 1 } { 2 } , - \frac { 1 } { 6 } , \frac { 1 } { 6 } , \frac { 1 } { 2 } , \frac { 5 } { 6 }$
C) $- \frac { 1 } { 2 } , - 1 , - \frac { 3 } { 2 } , - 2 , - \frac { 5 } { 2 }$
D) $- \frac { 1 } { 2 } , - \frac { 5 } { 6 } , - 1 , - \frac { 4 } { 3 } , - \frac { 5 } { 3 }$

Question

Write Terms of an Arithmetic Sequence
-$$a _ { n } = a _ { n  - 1} - \frac { 1 } { 3 } ; a _ { 1 } = - \frac { 1 } { 2 }$$
A) $- \frac { 1 } { 2 } , - \frac { 5 } { 6 } , - \frac { 7 } { 6 } , - \frac { 3 } { 2 } , - \frac { 11 } { 6 }$
B) $- \frac { 1 } { 2 } , - \frac { 1 } { 6 } , \frac { 1 } { 6 } , \frac { 1 } { 2 } , \frac { 5 } { 6 }$
C) $- \frac { 1 } { 2 } , - 1 , - \frac { 3 } { 2 } , - 2 , - \frac { 5 } { 2 }$
D) $- \frac { 1 } { 2 } , - \frac { 5 } { 6 } , - 1 , - \frac { 4 } { 3 } , - \frac { 5 } { 3 }$

Quizplus · Accepted Answer

Given the arithmetic sequence formula $a_n = a_{n-1} - \frac{1}{3}$ with the first term $a_1 = -\frac{1}{2}$, each subsequent term is found by subtracting $\frac{1}{3}$ from the previous term. Starting with $-\frac{1}{2}$ and subtracting $\frac{1}{3}$ for each next term, the sequence matches option A.

Write Terms of an Arithmetic Sequence - an=an−1−13;a1=−12a _ { n } = a _ { n - 1} - \frac { 1 } { 3 } ; a _ { 1 } = - \frac { 1 } { 2 }an​=an−1​−31​;a1​=−21​

Write Terms of an Arithmetic Sequence
- $a _ { n } = a _ { n - 1} - \frac { 1 } { 3 } ; a _ { 1 } = - \frac { 1 } { 2 }$