Write the first four terms of the sequence whose general term is given.
-$$a _ { n } = \frac { ( - 1 ) ^ { n + 1 } } { n + 2 }$$
A) $\frac { 1 } { 3 } , - \frac { 1 } { 4 } , \frac { 1 } { 5 } , - \frac { 1 } { 6 }$
B) $- \frac { 1 } { 3 } , \frac { 1 } { 4 } , - \frac { 1 } { 5 } , \frac { 1 } { 6 }$
C) $\frac { 1 } { 3 } , - \frac { 1 } { 8 } , \frac { 1 } { 15 } , - \frac { 1 } { 24 }$
D) $- \frac { 1 } { 4 } , \frac { 1 } { 5 } , - \frac { 1 } { 6 } , \frac { 1 } { 7 }$

Question

Quizplus · Accepted Answer

The general term of the sequence is $a_n = \frac{(-1)^{n+1}}{n+2}$. Substituting $n = 1, 2, 3, 4$ gives the first four terms as $\frac{1}{3}, -\frac{1}{4}, \frac{1}{5}, -\frac{1}{6}$ respectively.

Write the First Four Terms of the Sequence Whose General an=(−1)n+1n+2a _ { n } = \frac { ( - 1 ) ^ { n + 1 } } { n + 2 }an​=n+2(−1)n+1​

Write the First Four Terms of the Sequence Whose General $a _ { n } = \frac { ( - 1 ) ^ { n + 1 } } { n + 2 }$