Solve the problem.
-The decay of 608 mg of an isotope is given by A $$A ( t ) = 608 e ^ { - 0.019 t }$$ , where t is time in years. Find the amount left after 50 years.
A) 235 mg
B) 231 mg
C) 597 mg
D) 118 mg

Question

Quizplus · Accepted Answer

The amount left after 50 years is calculated by substituting t = 50 into the decay formula: A(50) = 608 * e^(-0.019 * 50). This evaluates to approximately 235 mg.

Solve the Problem A(t)=608e−0.019tA ( t ) = 608 e ^ { - 0.019 t }A(t)=608e−0.019t

Solve the Problem $A ( t ) = 608 e ^ { - 0.019 t }$