Use power series operations to find the Taylor series at x = 0 for the given function.
-$$x ^ { 8 } e ^ { x }$$
A) $\sum _ { n = 0 } ^ { \infty } \frac { 8 ^ { n _ { x ^ { n } } } } { n ! }$
B) $\sum _ { n = 0 } ^ { \infty } \frac { x ^ { n + 8 } } { n ! }$
C) $\sum _ { n = 0 } ^ { \infty } \frac { 8 ^ { n _ { x } n } } { ( n + 8 ) ! }$
D) $\sum _ { n = 0 } ^ { \infty } \frac { x ^ { n + 8 } } { ( n + 8 ) ! }$

Question

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The Answer of Use power series operations to find the Taylor series at x = 0 for the given function.
-$$x ^ { 8 } e ^ { x }$$
A) $\sum _ { n = 0 } ^ { \infty } \frac { 8 ^ { n _ { x ^ { n } } } } { n ! }$
B) $\sum _ { n = 0 } ^ { \infty } \frac { x ^ { n + 8 } } { n ! }$
C) $\sum _ { n = 0 } ^ { \infty } \frac { 8 ^ { n _ { x } n } } { ( n + 8 ) ! }$
D) $\sum _ { n = 0 } ^ { \infty } \frac { x ^ { n + 8 } } { ( n + 8 ) ! }$

Use Power Series Operations to Find the Taylor Series at X