Find the quadratic approximation of f at x = 0.
-$$f ( x ) = \sqrt { 16 - x ^ { 2 } }$$
A) $Q ( x ) = 4 - \frac { x ^ { 2 } } { 4 }$
B) $Q ( x ) = 4 + \frac { x ^ { 2 } } { 8 }$
C) $Q ( x ) = 4 + \frac { x ^ { 2 } } { 4 }$
D) $Q ( x ) = 4 - \frac { x ^ { 2 } } { 8 }$

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The Answer of Find the quadratic approximation of f at x = 0.
-$$f ( x ) = \sqrt { 16 - x ^ { 2 } }$$
A) $Q ( x ) = 4 - \frac { x ^ { 2 } } { 4 }$
B) $Q ( x ) = 4 + \frac { x ^ { 2 } } { 8 }$
C) $Q ( x ) = 4 + \frac { x ^ { 2 } } { 4 }$
D) $Q ( x ) = 4 - \frac { x ^ { 2 } } { 8 }$

Find the Quadratic Approximation of F at X = 0 f(x)=16−x2f ( x ) = \sqrt { 16 - x ^ { 2 } }f(x)=16−x2​

Find the Quadratic Approximation of F at X = 0 $f ( x ) = \sqrt { 16 - x ^ { 2 } }$