Solve the problem.
-A bullet is fired with a muzzle velocity of $1251 \mathrm { ft } / \mathrm { sec }$ from a gun aimed at an angle of $29 ^ { \circ }$ above the horizontal. Find the vertical component of the velocity.
A) 606.5 ft/sec
B) 693.4 ft/sec
C) -935.8 ft/sec
D) 1094 ft/sec

Question

Quizplus · Accepted Answer

The vertical component of velocity can be found by using the formula:

$v _ { v } = v \sin \theta$

where $v$ is the muzzle velocity and $\theta$ is the angle of elevation.

Plugging in the given values, we get:

$v _ { v } = 1251 \mathrm { ft } / \mathrm { sec } \times \sin 29 ^ { \circ } \approx 606.5 \mathrm { ft } / \mathrm { sec }$

Therefore, the vertical component of the velocity is approximately 606.5 ft/sec. Option A is the correct choice.

Solve the Problem 1251ft/sec1251 \mathrm { ft } / \mathrm { sec }1251ft/sec

Solve the Problem $1251 \mathrm { ft } / \mathrm { sec }$