Solve the Problem $3.2 \mathrm { ft }$ Above the Ground $142 \mathrm { ft } / \mathrm { sec }$

Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the launch angle is measured from the horizontal, and that the projectile is launched from the origin over a horizontal surface
-A baseball is hit when it is $3.2 \mathrm { ft }$ above the ground. It leaves the bat with an initial velocity of $142 \mathrm { ft } / \mathrm { sec }$ at a launch angle of $30 ^ { \circ }$ . At the instant the ball is hit, an instantaneous gust of wind blows against the ball, adding a component of $- 10.3 \mathrm { i } ( \mathrm { ft } / \mathrm { sec }$ ) to the ball's initial velocity. How high does the baseball go? Round your answer to the nearest tenth.

A) 71.0 ft
B) 84.0 ft
C) 82.0 ft
D) 78.8 ft