Use polar coordinates to find the limit of the function as (x, y) approaches (0, 0).
-$$f ( x , y ) = \cos \left( \frac { x ^ { 2 } } { x ^ { 2 } + y ^ { 2 } } \right)$$
A) 1
B) $\frac { \pi } { 2 }$
C) 0
D) No limit

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The Answer of Use polar coordinates to find the limit of the function as (x, y) approaches (0, 0).
-$$f ( x , y ) = \cos \left( \frac { x ^ { 2 } } { x ^ { 2 } + y ^ { 2 } } \right)$$
A) 1
B) $\frac { \pi } { 2 }$
C) 0
D) No limit

Use Polar Coordinates to Find the Limit of the Function f(x,y)=cos⁡(x2x2+y2)f ( x , y ) = \cos \left( \frac { x ^ { 2 } } { x ^ { 2 } + y ^ { 2 } } \right)f(x,y)=cos(x2+y2x2​)

Use Polar Coordinates to Find the Limit of the Function $f ( x , y ) = \cos \left( \frac { x ^ { 2 } } { x ^ { 2 } + y ^ { 2 } } \right)$