Find two paths of approach from which one can conclude that the function has no limit as (x, y) approaches (0, 0).
-$$f ( x , y ) = \frac { x ^ { 2 } y } { x ^ { 4 } + y ^ { 2 } }$$

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The Answer of Find two paths of approach from which one can conclude that the function has no limit as (x, y) approaches (0, 0).
-$$f ( x , y ) = \frac { x ^ { 2 } y } { x ^ { 4 } + y ^ { 2 } }$$

Find Two Paths of Approach from Which One Can Conclude f(x,y)=x2yx4+y2f ( x , y ) = \frac { x ^ { 2 } y } { x ^ { 4 } + y ^ { 2 } }f(x,y)=x4+y2x2y​

Find Two Paths of Approach from Which One Can Conclude $f ( x , y ) = \frac { x ^ { 2 } y } { x ^ { 4 } + y ^ { 2 } }$