Find the specific function value.
-Find $f ( 3,6 )$ when $f ( x , y ) = \sqrt { 3 x + y ^ { 2 } }$.
A) 10
B) $5 \sqrt { 3 }$
C) 9
D) $3 \sqrt { 5 }$

Name: Find the specific function value. -Find $f ( 3,6 )$ when $f ( x , y ) = \sqrt { 3 x + y ^ { 2 } }$. A) 10 B) $5 \sqrt { 3 }$ C) 9 D) $3 \sqrt { 5 }$
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Question

Quizplus · Accepted Answer

Substituting in $x=3$ and $y=6$ into the function $f(x,y)=\sqrt{3x+y^2}$ results in 
$$f(3,6)=\sqrt{3(3)+(6)^{2}}=\sqrt{9+36}=\sqrt{45}=3\sqrt{5}$$
Therefore, the answer is choice D.

Find the Specific Function Value f(3,6)f ( 3,6 )f(3,6) When f(x,y)=3x+y2f ( x , y ) = \sqrt { 3 x + y ^ { 2 } }f(x,y)=3x+y2​

Find the Specific Function Value $f ( 3,6 )$ When $f ( x , y ) = \sqrt { 3 x + y ^ { 2 } }$