Find the intervals on which the function is continuous.
-$$y = \sqrt { 8 x + 8 }$$
A) continuous on the interval $( - 1 , \infty )$
B) continuous on the interval $[ - 1 , \infty )$
C) continuous on the interval $( - \infty , - 1 ]$
D) continuous on the interval $[ 1 , \infty )$

Question

Quizplus · Accepted Answer

For a square root function to be continuous, the expression inside the square root must be nonnegative. So we must solve the inequality $8x+8\geq 0$:
\begin{align*}
8x+8&\geq 0 \
8(x+1) &\geq 0 \
x &\geq -1
\end{align*}
Therefore, the function is continuous on $[-1,\infty)$.

Find the Intervals on Which the Function Is Continuous y=8x+8y = \sqrt { 8 x + 8 }y=8x+8​

Find the Intervals on Which the Function Is Continuous $y = \sqrt { 8 x + 8 }$