Find the intervals on which the function is continuous.
-$$y = \frac { \sin ( 3 \theta ) } { 5 \theta }$$
A) discontinuous only when $\theta = \pi$
B) discontinuous only when $\theta = 0$
C) continuous everywhere
D) discontinuous only when $\theta = \frac { \pi } { 2 }$

Question

Quizplus · Accepted Answer

The function $y = \frac { \sin ( 3 \theta ) } { 5 \theta }$ is continuous everywhere except at $\theta = 0$, where the denominator becomes zero, causing the function to be undefined. Everywhere else, both the numerator and denominator are continuous, making the function continuous.

Find the Intervals on Which the Function Is Continuous y=sin⁡(3θ)5θy = \frac { \sin ( 3 \theta ) } { 5 \theta }y=5θsin(3θ)​

Find the Intervals on Which the Function Is Continuous $y = \frac { \sin ( 3 \theta ) } { 5 \theta }$