Answer the question.
-Does $\lim _ { x \rightarrow 1 ^ { + } } f ( x ) = f ( - 1 ) ?$
$\mathrm { f } ( \mathrm { x } ) = \left\{ \begin{array} { l l }
- \mathrm { x } ^ { 2 } + 1 , & - 1 \leq \mathrm { x }

Question

Answer the question.
-Does $\lim _ { x \rightarrow 1 ^ { + } } f ( x ) = f ( - 1 ) ?$
$\mathrm { f } ( \mathrm { x } ) = \left\{ \begin{array} { l l } 
- \mathrm { x } ^ { 2 } + 1 , & - 1 \leq \mathrm { x } < 0 \
2 \mathrm { x } , & 0 < \mathrm { x } < 1 \
- 4 , & \mathrm { x } = 1 \
- 2 \mathrm { x } + 4 & 1 < \mathrm { x } < 3 \
3 , & 3 < \mathrm { x } < 5
\end{array} \right.$

Quizplus · Accepted Answer

As x approaches 1 from the right, the function approaches the value of -4 (since that is the value of f(1)). Similarly, f(-1) is also -4. Therefore, the limit is equal to f(-1), and the answer is true.

Answer the Question lim⁡x→1+f(x)=f(−1)?\lim _ { x \rightarrow 1 ^ { + } } f ( x ) = f ( - 1 ) ?limx→1+​f(x)=f(−1)?

Answer the Question $\lim _ { x \rightarrow 1 ^ { + } } f ( x ) = f ( - 1 ) ?$