$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow - } \frac { \sin ( \sin x ) } { \sin x }$$
A) 1
B) 0
C) -1
D) does not exist

Question

Quizplus · Accepted Answer

The limit can be solved by substituting $\sin x$ with a new variable, say $y$, where $y = \sin x$. As $x \rightarrow 0$, $y \rightarrow 0$. Thus, the limit becomes $\lim _ { y \rightarrow 0 } \frac { \sin y } { y }$, which is known to be 1.

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$