$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow 0 } \frac { \sin 5 x } { x }$$
A) 1
B) does not exist
C) 5
D) $\frac { 1 } { 5 }$

Question

Quizplus · Accepted Answer

Using the property of limit, we have
$$\lim_{x\rightarrow 0} \frac{\sin 5x}{x} = 5\cdot\lim_{x\rightarrow 0} \frac{\sin 5x}{5x} = 5\cdot 1 = 5$$
Therefore, the answer is (C) 5.

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$