Solve the Problem $s$ And the Height $h$ By the Formula $\mathrm { V } = \frac { 1 } { 3 } \mathrm {~s} ^ { 2 } \mathrm {~h} .$

Solve the problem.
-The volume of a square pyramid is related to the length of a side of the base $s$ and the height $h$ by the formula $\mathrm { V } = \frac { 1 } { 3 } \mathrm {~s} ^ { 2 } \mathrm {~h} .$ How is $\mathrm { dV } / \mathrm { dt }$ related to $\mathrm { ds } / \mathrm { dt }$ if $\mathrm { h }$ is constant?

A) $\frac { \mathrm { dV } } { \mathrm { dt } } = \frac { 2 \mathrm {~s} } { 3 } \frac { \mathrm { ds } } { \mathrm { dt } }$
B) $\frac { d V } { d t } = \frac { 2 h s } { 3 } \frac { d s } { d t }$
C) $\frac { d V } { d t } = \frac { s ^ { 2 } } { 3 } \frac { d s } { d t }$
D) $\frac { \mathrm { dV } } { \mathrm { dt } } = \frac { \mathrm { h } } { 3 } \frac { \mathrm { ds } } { \mathrm { dt } }$