L'Hopital's rule does not help with the given limit. Find the limit some other way.
-$\lim _ { x \rightarrow 0 } \frac { x \cot x } { \cos x }$
A) $\infty$
B) $- 1$
C) 1
D) 0

Question

Quizplus · Accepted Answer

We can rewrite the expression as $$\lim_{x\rightarrow 0}\frac{x}{\sin x}$$ Then, using the fact that $\lim_{\theta\rightarrow 0}\frac{\sin \theta}{\theta} = 1$, we have that the limit is equal to $\boxed{1}$.

L'Hopital's Rule Does Not Help with the Given Limit lim⁡x→0xcot⁡xcos⁡x\lim _ { x \rightarrow 0 } \frac { x \cot x } { \cos x }limx→0​cosxxcotx​

L'Hopital's Rule Does Not Help with the Given Limit $\lim _ { x \rightarrow 0 } \frac { x \cot x } { \cos x }$