Solve the problem.
-Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, ﬁnd the body's position at time t.
A = 16 cos 5t, v(0) = -5, s(0) = 4
A) $s = - \frac { 16 } { 25 } \sin 5 t - 5 t + 4$
B) $s = - \frac { 16 } { 25 } \cos 5 t - 5 t + 4$
C) $\mathrm { s } = \frac { 16 } { 25 } \cos 5 \mathrm { t } + 5 \mathrm { t } + 4$
D) $s = \frac { 16 } { 25 } \sin 5 t - 5 t + 4$

Question

Solve the problem.
-Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, ﬁnd the body's position at time t.
A = 16 cos 5t, v(0) = -5, s(0) = 4 
A) $s = - \frac { 16 } { 25 } \sin 5 t - 5 t + 4$
B) $s = - \frac { 16 } { 25 } \cos 5 t - 5 t + 4$
C) $\mathrm { s } = \frac { 16 } { 25 } \cos 5 \mathrm { t } + 5 \mathrm { t } + 4$
D) $s = \frac { 16 } { 25 } \sin 5 t - 5 t + 4$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, ﬁnd the body's position at time t.
A = 16 cos 5t, v(0) = -5, s(0) = 4 
A) $s = - \frac { 16 } { 25 } \sin 5 t - 5 t + 4$
B) $s = - \frac { 16 } { 25 } \cos 5 t - 5 t + 4$
C) $\mathrm { s } = \frac { 16 } { 25 } \cos 5 \mathrm { t } + 5 \mathrm { t } + 4$
D) $s = \frac { 16 } { 25 } \sin 5 t - 5 t + 4$

Solve the Problem s=−1625sin⁡5t−5t+4s = - \frac { 16 } { 25 } \sin 5 t - 5 t + 4s=−2516​sin5t−5t+4

Solve the Problem $s = - \frac { 16 } { 25 } \sin 5 t - 5 t + 4$