Solve the initial value problem.
-$$\frac { d y } { d x } = \sin ( 4 x + \pi ) , y ( 0 ) = 2$$
A) $y = - \cos ( 4 x + \pi ) + 1$
B) $\mathrm { y } = - \frac { 1 } { 4 } \cos ( 4 \mathrm { x } + \pi ) + \frac { 7 } { 4 }$
C) $y = 4 \cos ( 4 x + \pi ) + 2$
D) $y = - \frac { 1 } { 4 } \cos ( 4 x + \pi ) + 2$

Question

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The Answer of Solve the initial value problem.
-$$\frac { d y } { d x } = \sin ( 4 x + \pi ) , y ( 0 ) = 2$$
A) $y = - \cos ( 4 x + \pi ) + 1$
B) $\mathrm { y } = - \frac { 1 } { 4 } \cos ( 4 \mathrm { x } + \pi ) + \frac { 7 } { 4 }$
C) $y = 4 \cos ( 4 x + \pi ) + 2$
D) $y = - \frac { 1 } { 4 } \cos ( 4 x + \pi ) + 2$

Solve the Initial Value Problem dydx=sin⁡(4x+π),y(0)=2\frac { d y } { d x } = \sin ( 4 x + \pi ) , y ( 0 ) = 2dxdy​=sin(4x+π),y(0)=2

Solve the Initial Value Problem $\frac { d y } { d x } = \sin ( 4 x + \pi ) , y ( 0 ) = 2$