Solve the problem.
-Suppose that $\int _ { 2 } ^ { 3 } \mathrm { f } ( \mathrm { x } ) \mathrm { dx } = 5$. Find $\int _ { 2 } ^ { 3 } 4 \mathrm { f } ( \mathrm { u } ) \mathrm { du }$ and $\int _ { 2 } ^ { 3 } - \mathrm { f } ( \mathrm { u } ) \mathrm { du }$.
A) $20 ; - 5$
B) $9 ; 5$
C) $4 ; - 5$
D) $20 ; \frac { 1 } { 5 }$

Question

Quizplus · Accepted Answer

The integral of a function multiplied by a constant is the constant multiplied by the integral of the function, so $4 \int _ { 2 } ^ { 3 } f ( u ) du = 4 \times 5 = 20$. Similarly, the integral of a function multiplied by -1 is the negative of the integral of the function, so $\int _ { 2 } ^ { 3 } - f ( u ) du = -5$.

Solve the Problem ∫23f(x)dx=5\int _ { 2 } ^ { 3 } \mathrm { f } ( \mathrm { x } ) \mathrm { dx } = 5∫23​f(x)dx=5

Solve the Problem $\int _ { 2 } ^ { 3 } \mathrm { f } ( \mathrm { x } ) \mathrm { dx } = 5$