Estimate the value of the quantity.
-A piece of tissue paper is picked up in gusty wind. The table shows the velocity of the paper at 2 second intervals. Estimate the distance the paper travelled using left-endpoints.
$\begin{array}{c|c}
\begin{array}{c}
\text { Time } \
(\mathrm{sec})
\end{array} & \begin{array}{c}
\text { Velocity } \
(\mathrm{ft} / \mathrm{sec})
\end{array} \
\hline 0 & 0 \
2 & 8 \
4 & 12 \
6 & 6 \
8 & 28 \
10 & 33 \
12 & 23 \
14 & 10 \
16 & 2
\end{array}$

A) 244 ft
B) 224 ft
C) 122 ft
D) 221 ft

Question

Estimate the value of the quantity.
-A piece of tissue paper is picked up in gusty wind. The table shows the velocity of the paper at 2 second intervals. Estimate the distance the paper travelled using left-endpoints.
$\begin{array}{c|c}
\begin{array}{c}
\text { Time } \
(\mathrm{sec})
\end{array} & \begin{array}{c}
\text { Velocity } \
(\mathrm{ft} / \mathrm{sec})
\end{array} \
\hline 0 & 0 \
2 & 8 \
4 & 12 \
6 & 6 \
8 & 28 \
10 & 33 \
12 & 23 \
14 & 10 \
16 & 2
\end{array}$

A) 244 ft
B) 224 ft
C) 122 ft
D) 221 ft

Quizplus · Accepted Answer

The left-endpoint approximation is given by:$$\sum_{n=1}^8 v(t_n) \Delta t$$where $v(t_n)$ is the velocity at time $t_n$ and $\Delta t$ is the time interval.In this case, $\Delta t = 2$ and the velocities are given in the table.Therefore, the left-endpoint approximation is:$$0(2) + 8(2) + 12(2) + 6(2) + 28(2) + 33(2) + 23(2) + 10(2) + 2(2) = 244$$So, the distance the paper travelled is approximately 244 ft.

Estimate the Value of the Quantity A) 244 Ft B) 224 Ft C) 122 Ft D)

Estimate the Value of the Quantity A) 244 Ft
B) 224 Ft
C) 122 Ft
D)