Solve the problem.
-The pulse rate for a species of small mammal follows a normal distribution with a mean $\mu = 205$ beats per minute and standard deviation $\sigma = 30$ beats per minute. In a population of 800 of these mammals, how many would you expect to have a pulse rate between 193 and 241 ?
A) $\approx 384$ of these mammals
B) $\approx 552$ of these mammals
C) $\approx 400$ of these mammals
D) $\approx 432$ of these mammals

Question

Quizplus · Accepted Answer

The z-scores for 193 and 241 are approximately -0.4 and 1.2, respectively. The probability of a z-score between -0.4 and 1.2 is about 0.54. Multiplying 0.54 by 800 gives approximately 432 mammals.

Solve the Problem μ=205\mu = 205μ=205 Beats Per Minute and Standard Deviation

Solve the Problem $\mu = 205$ Beats Per Minute and Standard Deviation