Find the area or volume.
-Find the area under the curve $y = \frac { 1 } { ( x + 1 ) ^ { 3 / 2 } }$ bounded on the left by $x = 15$.
A) $\frac { 2 } { 15 }$
B) $\frac { 1 } { 2 }$
C) 8
D) $\frac { 1 } { 4 }$

Question

Quizplus · Accepted Answer

The area under the curve can be found by integrating the function from 15 to infinity. The integral of $y = \frac{1}{(x+1)^{3/2}}$ is $-\frac{2}{\sqrt{x+1}}$. Evaluating this from 15 to infinity gives $\frac{1}{2}$.

Find the Area or Volume y=1(x+1)3/2y = \frac { 1 } { ( x + 1 ) ^ { 3 / 2 } }y=(x+1)3/21​

Find the Area or Volume $y = \frac { 1 } { ( x + 1 ) ^ { 3 / 2 } }$