Evaluate the integral by making a substitution and then using a table of integrals.
-$$\int \tan ^ { - 1 } \sqrt { x + 2 } d x$$
A) $\frac { 1 } { 2 } ( x + 2 ) \sin ^ { - 1 } \sqrt { x + 2 } - \sqrt { x + 2 } + C$
B) $( x + 3 ) \tan ^ { - 1 } \sqrt { x + 2 } - \sqrt { x + 2 } + C$
C) $\frac { 1 } { 4 } ( 2 x + 3 ) \sin ^ { - 1 } \sqrt { x + 2 } + \frac { \sqrt { x + 2 } } { 4 } \sqrt { - x - 1 } + C$
D) $\frac { 1 } { 2 } ( x + 3 ) \tan ^ { - 1 } \sqrt { x + 2 } - \frac { \sqrt { x + 2 } } { 2 } + C$

Question

Quizplus · Accepted Answer

The Answer of Evaluate the integral by making a substitution and then using a table of integrals.
-$$\int \tan ^ { - 1 } \sqrt { x + 2 } d x$$
A) $\frac { 1 } { 2 } ( x + 2 ) \sin ^ { - 1 } \sqrt { x + 2 } - \sqrt { x + 2 } + C$
B) $( x + 3 ) \tan ^ { - 1 } \sqrt { x + 2 } - \sqrt { x + 2 } + C$
C) $\frac { 1 } { 4 } ( 2 x + 3 ) \sin ^ { - 1 } \sqrt { x + 2 } + \frac { \sqrt { x + 2 } } { 4 } \sqrt { - x - 1 } + C$
D) $\frac { 1 } { 2 } ( x + 3 ) \tan ^ { - 1 } \sqrt { x + 2 } - \frac { \sqrt { x + 2 } } { 2 } + C$

Evaluate the Integral by Making a Substitution and Then Using ∫tan⁡−1x+2dx\int \tan ^ { - 1 } \sqrt { x + 2 } d x∫tan−1x+2​dx

Evaluate the Integral by Making a Substitution and Then Using $\int \tan ^ { - 1 } \sqrt { x + 2 } d x$