The autonomous differential equation represents a model for population growth. Use phase line analysis to sketch solution curves for P(t), selecting different starting values P(0). Which equilibria are stable, and which are unstable?
-$\frac { \mathrm { dP } } { \mathrm { dt } } = \mathrm { P } ( \mathrm { P } - 5 )$

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The Answer of The autonomous differential equation represents a model for population growth. Use phase line analysis to sketch solution curves for P(t), selecting different starting values P(0). Which equilibria are stable, and which are unstable?
-$\frac { \mathrm { dP } } { \mathrm { dt } } = \mathrm { P } ( \mathrm { P } - 5 )$

The Autonomous Differential Equation Represents a Model for Population Growth dPdt=P(P−5)\frac { \mathrm { dP } } { \mathrm { dt } } = \mathrm { P } ( \mathrm { P } - 5 )dtdP​=P(P−5)

The Autonomous Differential Equation Represents a Model for Population Growth $\frac { \mathrm { dP } } { \mathrm { dt } } = \mathrm { P } ( \mathrm { P } - 5 )$