Solve the initial value problem.
-$$\frac { d y } { d x } + x y = 4 x ; y ( 0 ) = - 4$$
A) $y = 4 e ^ { x ^ { 2 } / 2 } - 8$
B) $y = 4 e ^ { - x ^ { 2 } / 2 } - 8$
C) $y = - 8 e ^ { x ^ { 2 } / 2 } + 4$
D) $y = - 8 e ^ { - x ^ { 2 } / 2 } + 4$

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The Answer of Solve the initial value problem.
-$$\frac { d y } { d x } + x y = 4 x ; y ( 0 ) = - 4$$
A) $y = 4 e ^ { x ^ { 2 } / 2 } - 8$
B) $y = 4 e ^ { - x ^ { 2 } / 2 } - 8$
C) $y = - 8 e ^ { x ^ { 2 } / 2 } + 4$
D) $y = - 8 e ^ { - x ^ { 2 } / 2 } + 4$

Solve the Initial Value Problem dydx+xy=4x;y(0)=−4\frac { d y } { d x } + x y = 4 x ; y ( 0 ) = - 4dxdy​+xy=4x;y(0)=−4

Solve the Initial Value Problem $\frac { d y } { d x } + x y = 4 x ; y ( 0 ) = - 4$