Suppose g : $\mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor .$
(a) Draw the graph of g .
(b) Is g 1-1?
(c) Is g onto $\mathbf { R }$ ?

Question

Suppose  g  : $\mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor .$
(a) Draw the graph of  g .
(b) Is  g  1-1?
(c) Is  g  onto $\mathbf { R }$  ?

Quizplus · Accepted Answer

The Answer of Suppose  g  : $\mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor .$
(a) Draw the graph of  g .
(b) Is  g  1-1?
(c) Is  g  onto $\mathbf { R }$  ?

Suppose G R→R\mathbf { R } \rightarrow \mathbf { R }R→R

Suppose G $\mathbf { R } \rightarrow \mathbf { R }$