Solve the problem.
-Let P = (x, y) be a point on the graph of y $$y = \sqrt { x }$$ . Express the distance d from P to the point (1, 0) as a function of x.
A) $d ( x ) = x ^ { 2 } - x + 1$
B) $d ( x ) = \sqrt { x ^ { 2 } - x + 1 }$
C) $d ( x ) = \sqrt { x ^ { 2 } + 2 x + 2 }$
D) $d ( x ) = x ^ { 2 } + 2 x + 2$

Question

Solve the problem.
-Let P = (x, y) be a point on the graph of y $$y = \sqrt { x }$$ . Express the distance d from P to the point (1, 0) as a function of x. 
A) $d ( x ) = x ^ { 2 } - x + 1$
B) $d ( x ) = \sqrt { x ^ { 2 } - x + 1 }$
C) $d ( x ) = \sqrt { x ^ { 2 } + 2 x + 2 }$
D) $d ( x ) = x ^ { 2 } + 2 x + 2$

Quizplus · Accepted Answer

The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Here, $x_1 = x$, $y_1 = \sqrt{x}$, $x_2 = 1$, and $y_2 = 0$. Substituting these values into the distance formula gives $d(x) = \sqrt{(1 - x)^2 + (0 - \sqrt{x})^2} = \sqrt{x^2 - 2x + 1 + x} = \sqrt{x^2 - x + 1}$.

Solve the Problem y=xy = \sqrt { x }y=x​ Express the Distance D from P to the Point

Solve the Problem $y = \sqrt { x }$ Express the Distance D from P to the Point