Find an equation of the secant line containing (1, f(1)) and (2, f(2)).
-$$f ( x ) = x ^ { 3 } - x$$
A) y = -6x + 6
B) y = 6x - 6
C) y = 6x + 6
D) y = -6x - 6

Question

Quizplus · Accepted Answer

First, calculate the values of $f(1)$ and $f(2)$. For $f(1) = 1^3 - 1 = 0$ and $f(2) = 2^3 - 2 = 6$. The slope of the secant line is $\frac{6 - 0}{2 - 1} = 6$. Using point-slope form with point (1, 0), the equation is $y - 0 = 6(x - 1)$, simplifying to $y = 6x - 6$.

Find an Equation of the Secant Line Containing (1, F(1)) f(x)=x3−xf ( x ) = x ^ { 3 } - xf(x)=x3−x

Find an Equation of the Secant Line Containing (1, F(1)) $f ( x ) = x ^ { 3 } - x$