In a standard normal distribution, the probability P(-1.00

Question

In a standard normal distribution, the probability P(-1.00< z < 1.20) is the same as:
A) P(1< z < 1.20) - P(0 < z < 1.00).
B) P(1< z < 1.20) - 2*P(0 < z < 1.00).
C) 2 ∗ P(1< z < 1.20) - P(0 < z <1.00).
D) P(1 < z < 1.20) + 2 ∗ P(0 < z <1.00).

Quizplus · Accepted Answer

The probability P(-1.00< z < 1.20) can be split into two parts: P(-1.00< z < 0) and P(0 < z < 1.20). The first part is equal to P(0 < z < 1.00) due to symmetry, and the second part is P(0 < z < 1.20). Therefore, the total probability is P(0 < z < 1.20) + P(0 < z < 1.00), which matches option D when rearranged.

In a Standard Normal Distribution, the Probability P(-1