Find $\lim _ { x \rightarrow \infty } \frac { 1 - 6 x } { 1 + 8 x }$ (if it exists).
A) 0
B) $- \frac { 3 } { 4 }$
C) $\frac { 3 } { 4 }$
D) $- \infty$
E) limit does not exist

Question

Quizplus · Accepted Answer

To find the limit as $x$ approaches infinity for the given function, divide the numerator and the denominator by $x$, the highest power of $x$ in the expression. This simplifies to $\lim _ { x \rightarrow \infty } \frac { \frac{1}{x} - 6 } { \frac{1}{x} + 8 }$. As $x$ approaches infinity, $\frac{1}{x}$ approaches 0, leaving $\frac{-6}{8}$, which simplifies to $-\frac{3}{4}$.

Find lim⁡x→∞1−6x1+8x\lim _ { x \rightarrow \infty } \frac { 1 - 6 x } { 1 + 8 x }limx→∞​1+8x1−6x​

Find $\lim _ { x \rightarrow \infty } \frac { 1 - 6 x } { 1 + 8 x }$