Find
$$\lim _ { x \rightarrow 6 } \frac { 4 x } { \sqrt { x + 4 } }$$
by direct substitution.
A) $\frac { 6 } { \sqrt { 10 } }$
B) $4 \sqrt { 6 }$
C) $24 \sqrt { 10 }$
D) 1
E) $\frac { 24 } { \sqrt { 10 } }$

Question

Quizplus · Accepted Answer

Direct substitution of $x = 6$ into the given limit expression $\frac { 4 x } { \sqrt { x + 4 } }$ gives $\frac { 4 \cdot 6 } { \sqrt { 6 + 4 } } = \frac { 24 } { \sqrt { 10 } }$.

Find lim⁡x→64xx+4\lim _ { x \rightarrow 6 } \frac { 4 x } { \sqrt { x + 4 } }x→6lim​x+4​4x​

Find $\lim _ { x \rightarrow 6 } \frac { 4 x } { \sqrt { x + 4 } }$