Use mathematical induction to prove the following for every positive integer $n$.
$\sum _ { i = 1 } ^ { n } \frac { 5 } { ( 2 i - 1 ) ( 2 i + 1 ) } = \frac { 5 n } { 2 n + 1 }$

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The Answer of Use mathematical induction to prove the following for every positive integer $n$.
$\sum _ { i = 1 } ^ { n } \frac { 5 } { ( 2 i - 1 ) ( 2 i + 1 ) } = \frac { 5 n } { 2 n + 1 }$

Use Mathematical Induction to Prove the Following for Every Positive nnn

Use Mathematical Induction to Prove the Following for Every Positive $n$