Solve using any method.
$$\left\{ \begin{aligned}
7 x + 6 y & = 15 \
y & = x - 7
\end{aligned} \right.$$
A) $( 7,0 )$
B) $\left( - 6 , \frac { 51 } { 7 } \right)$
C) $\left( - \frac { 27 } { 13 } , - \frac { 64 } { 13 } \right)$
D) $\left( \frac { 57 } { 13 } , - \frac { 34 } { 13 } \right)$
E) inconsistent

Question

Quizplus · Accepted Answer

Substitute the second equation into the first equation and solve for x.$7x + 6(x - 7) = 15$$7x + 6x - 42 = 15$$13x = 57$$x = \frac{57}{13}$Substitute the value of x back into the second equation to solve for y.$y = \frac{57}{13} - 7$$y = -\frac{34}{13}$Therefore, the solution to the system of equations is $\left( \frac{57}{13}, -\frac{34}{13} \right)$.

Solve Using Any Method {7x+6y=15y=x−7\left\{ \begin{aligned}7 x + 6 y & = 15 \\y & = x - 7\end{aligned} \right.{7x+6yy​=15=x−7​

Solve Using Any Method $\left\{ \begin{aligned}7 x + 6 y & = 15 \\y & = x - 7\end{aligned} \right.$