Solve the system of equations algebraically.
$$\left\{ \begin{array} { r }
x y + 25 = 0 \
49 x - 100 y - 700 = 0
\end{array} \right.$$
A) $\left( 50 , - \frac { 1 } { 2 } \right)$
B) $\left( - 50 , \frac { 1 } { 2 } \right) , \left( 50 , - \frac { 1 } { 2 } \right)$
C) $\left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
D) $\left( - \frac { 50 } { 7 } , \frac { 7 } { 2 } \right) , \left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
E) no solution

Question

Solve the system of equations algebraically.
$$\left\{ \begin{array} { r } 
x y + 25 = 0 \
49 x - 100 y - 700 = 0
\end{array} \right.$$
A) $\left( 50 , - \frac { 1 } { 2 } \right)$
B) $\left( - 50 , \frac { 1 } { 2 } \right) , \left( 50 , - \frac { 1 } { 2 } \right)$
C) $\left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
D) $\left( - \frac { 50 } { 7 } , \frac { 7 } { 2 } \right) , \left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
E) no solution

Quizplus · Accepted Answer

The Answer of Solve the system of equations algebraically.
$$\left\{ \begin{array} { r } 
x y + 25 = 0 \
49 x - 100 y - 700 = 0
\end{array} \right.$$
A) $\left( 50 , - \frac { 1 } { 2 } \right)$
B) $\left( - 50 , \frac { 1 } { 2 } \right) , \left( 50 , - \frac { 1 } { 2 } \right)$
C) $\left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
D) $\left( - \frac { 50 } { 7 } , \frac { 7 } { 2 } \right) , \left( \frac { 50 } { 7 } , - \frac { 7 } { 2 } \right)$
E) no solution

Solve the System of Equations Algebraically {xy+25=049x−100y−700=0\left\{ \begin{array} { r } x y + 25 = 0 \\49 x - 100 y - 700 = 0\end{array} \right.{xy+25=049x−100y−700=0​

Solve the System of Equations Algebraically $\left\{ \begin{array} { r } x y + 25 = 0 \\49 x - 100 y - 700 = 0\end{array} \right.$