Find the equation of the circle
$x ^ { 2 } + y ^ { 2 } + D x + E y + F = 0$
that passes through the points $( 1,9 ) , ( - 4,4 ) , ( 6,4 )$.
A) $x ^ { 2 } + y ^ { 2 } - 2 x - 8 y - 8 = 0$
B) $x ^ { 2 } + y ^ { 2 } - x - 4 y - 8 = 0$
C) $x ^ { 2 } + y ^ { 2 } - 2 x - 8 y + 42 = 0$
D) $x ^ { 2 } + y ^ { 2 } - 2 x - 8 y - 25 = 0$
E) $x ^ { 2 } + y ^ { 2 } - x - 4 y - 25 = 0$

Question

Quizplus · Accepted Answer

By substituting the points into the general circle equation and solving the resulting system of equations, we find that the correct equation is $x^2 + y^2 - 2x - 8y - 8 = 0$.

Find the Equation of the Circle x2+y2+Dx+Ey+F=0x ^ { 2 } + y ^ { 2 } + D x + E y + F = 0x2+y2+Dx+Ey+F=0

Find the Equation of the Circle $x ^ { 2 } + y ^ { 2 } + D x + E y + F = 0$