Solve using any method.
$$\left\{ \begin{aligned}
- 7 x - 9 y & = - 6 \
y & = x - 3
\end{aligned} \right.$$
A) $( 2 , - 1 )$
B) $\left( 1 , - \frac { 3 } { 7 } \right)$
C) $\left( - \frac { 21 } { 16 } , - \frac { 27 } { 16 } \right)$
D) $\left( \frac { 33 } { 16 } , - \frac { 15 } { 16 } \right)$
E) inconsistent

Question

Quizplus · Accepted Answer

Substitute the second equation into the first equation and solve for x.$ - 7 x - 9 ( x - 3 ) = - 6 $$ - 7 x - 9 x + 27 = - 6 $$ - 16 x = - 33 $$ x = \frac { 33 } { 16 } $Substitute the value of x back into the second equation to solve for y.$ y = \frac { 33 } { 16 } - 3 $$ y = - \frac { 15 } { 16 } $Therefore, the solution is $ \left( \frac { 33 } { 16 } , - \frac { 15 } { 16 } \right) $.

Solve Using Any Method {−7x−9y=−6y=x−3\left\{ \begin{aligned}- 7 x - 9 y & = - 6 \\y & = x - 3\end{aligned} \right.{−7x−9yy​=−6=x−3​

Solve Using Any Method $\left\{ \begin{aligned}- 7 x - 9 y & = - 6 \\y & = x - 3\end{aligned} \right.$