Evaluate, if possible, the given trigonometric function at the indicated value.
$$\sin t , t = \frac { 4 \pi } { 3 }$$
A) $- \frac { \sqrt { 3 } } { 2 }$
B) $- \frac { 1 } { 2 }$
C) $- \frac { 2 \sqrt { 3 } } { 3 }$
D) $\frac { \sqrt { 3 } } { 2 }$
E) not possible

Question

Quizplus · Accepted Answer

The sine of $t = \frac{4\pi}{3}$ is $-\frac{\sqrt{3}}{2}$ because $\frac{4\pi}{3}$ is in the third quadrant where sine is negative, and the reference angle is $\frac{\pi}{3}$, whose sine is $\frac{\sqrt{3}}{2}$.

Evaluate, If Possible, the Given Trigonometric Function at the Indicated sin⁡t,t=4π3\sin t , t = \frac { 4 \pi } { 3 }sint,t=34π​

Evaluate, If Possible, the Given Trigonometric Function at the Indicated $\sin t , t = \frac { 4 \pi } { 3 }$