Find the point $( x , y )$ on the unit circle corresponding to the real number $t = \frac { 11 \pi } { 6 }$.
A) $\left( - \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)$
B) $\left( \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)$
C) $\left( - \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)$
D) $\left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)$
E) $\left( \frac { \sqrt { 2 } } { 2 } , \frac { \sqrt { 2 } } { 2 } \right)$

Question

Quizplus · Accepted Answer

The point on the unit circle corresponding to $t = \frac{11\pi}{6}$ can be found by evaluating the sine and cosine of $t$. For $t = \frac{11\pi}{6}$, $\cos(t) = \frac{\sqrt{3}}{2}$ and $\sin(t) = -\frac{1}{2}$, which corresponds to choice B.

Find the Point (x,y)( x , y )(x,y) On the Unit Circle Corresponding to the Real Number

Find the Point $( x , y )$ On the Unit Circle Corresponding to the Real Number