Determine the value that $f ( x ) = \frac { 4 x - 6 } { x ^ { 2 } - 7 }$ approaches as $x$ increases and decreases in magnitude without bound.
A) 8
B) 6
C) 4
D) 2
E) 0

Question

Quizplus · Accepted Answer

As $x$ increases or decreases without bound, the value of $f(x)$ approaches 0. This is because the degree of the polynomial in the denominator is higher than that in the numerator, causing the fraction to approach 0 as $x$ becomes very large or very small.

Determine the Value That f(x)=4x−6x2−7f ( x ) = \frac { 4 x - 6 } { x ^ { 2 } - 7 }f(x)=x2−74x−6​

Determine the Value That $f ( x ) = \frac { 4 x - 6 } { x ^ { 2 } - 7 }$