Use function notation to write $g$ in terms of $f ( x ) = \sqrt { x }$. $g ( x ) = - \frac { 1 } { 3 } \sqrt { x - 8 } + 7$
A) $g ( x ) = - f ( x - 8 ) + 6$
B) $\quad g ( x ) = - \frac { 1 } { 3 } f ( x ) - 1$
C) $g ( x ) = - \frac { 1 } { 3 } f ( x - 8 ) + 7$
D) $\quad g ( x ) = f ( x ) + 7$
E) $\quad g ( x ) = f ( x - 8 ) - \frac { 7 } { 3 }$

Question

Quizplus · Accepted Answer

Given $f(x) = \sqrt{x}$, $g(x) = -\frac{1}{3}\sqrt{x-8}+7$ can be rewritten using $f$ by substituting $x-8$ into $f$, resulting in $g(x) = -\frac{1}{3}f(x-8)+7$.

Use Function Notation to Write ggg In Terms Of f(x)=xf ( x ) = \sqrt { x }f(x)=x​

Use Function Notation to Write $g$ In Terms Of $f ( x ) = \sqrt { x }$