Find the domain of the function.
$f ( y ) = \sqrt { 9 - y ^ { 2 } }$
A) $- 3 \leq y \leq 3$
B) $y \leq - 3$ or $y \geq 3$
C) $y \geq 0$
D) $y \leq 3$
E) all real numbers

Question

Quizplus · Accepted Answer

The domain of $f(y) = \sqrt{9 - y^2}$ consists of all values of $y$ for which the expression under the square root, $9 - y^2$, is greater than or equal to 0. Solving the inequality $9 - y^2 \geq 0$ leads to $(-3 \leq y) \land (y \leq 3)$, which corresponds to option A: $-3 \leq y \leq 3$.

Find the Domain of the Function f(y)=9−y2f ( y ) = \sqrt { 9 - y ^ { 2 } }f(y)=9−y2​

Find the Domain of the Function $f ( y ) = \sqrt { 9 - y ^ { 2 } }$