Solved

Find the Slope of the Line Determined by the Given $= \frac { 5 } { 3 }$

Question 107

Multiple Choice

Find the slope of the line determined by the given equation and then sketch the line.
-3x + 5y = 16 $Find the slope of the line determined by the given equation and then sketch the line. -3x + 5y = 16 A) slope = \frac { 5 } { 3 } B) slope = - \frac { 3 } { 5 } C) slope = \frac { 3 } { 5 } D) slope = - \frac { 5 } { 3 }$

A) slope $= \frac { 5 } { 3 }$
$Find the slope of the line determined by the given equation and then sketch the line. -3x + 5y = 16 A) slope = \frac { 5 } { 3 } B) slope = - \frac { 3 } { 5 } C) slope = \frac { 3 } { 5 } D) slope = - \frac { 5 } { 3 }$
B) slope $= - \frac { 3 } { 5 }$
$Find the slope of the line determined by the given equation and then sketch the line. -3x + 5y = 16 A) slope = \frac { 5 } { 3 } B) slope = - \frac { 3 } { 5 } C) slope = \frac { 3 } { 5 } D) slope = - \frac { 5 } { 3 }$
C) slope $= \frac { 3 } { 5 }$
$Find the slope of the line determined by the given equation and then sketch the line. -3x + 5y = 16 A) slope = \frac { 5 } { 3 } B) slope = - \frac { 3 } { 5 } C) slope = \frac { 3 } { 5 } D) slope = - \frac { 5 } { 3 }$
D) slope $= - \frac { 5 } { 3 }$
$Find the slope of the line determined by the given equation and then sketch the line. -3x + 5y = 16 A) slope = \frac { 5 } { 3 } B) slope = - \frac { 3 } { 5 } C) slope = \frac { 3 } { 5 } D) slope = - \frac { 5 } { 3 }$