Find the center and radius of the circle with the given equation.
-$$( x - 4 ) ^ { 2 } + y ^ { 2 } = 16$$
A) Center $( 0,4 ) , r = 16$
B) Center $( 4,0 ) , r = 16$
C) Center $( 4,0 ) , \mathrm { r } = 4$
D) Center $( 0,4 ) , \mathrm { r } = 4$

Question

Quizplus · Accepted Answer

The equation of a circle in the form $(x - h)^2 + (y - k)^2 = r^2$ has a center at $(h, k)$ and a radius $r$. For the given equation $(x - 4)^2 + y^2 = 16$, the center is $(4, 0)$ and the radius is $\sqrt{16} = 4$.

Find the Center and Radius of the Circle with the Given