Write the standard form of the equation of the circle.
-Center (5, 7), r = 12
A) $( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 144$
B) $( \mathrm { x } + 5 ) ^ { 2 } + ( \mathrm { y } + 7 ) ^ { 2 } = 12$
C) $( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 12$
D) $( x + 5 ) ^ { 2 } + ( y + 7 ) ^ { 2 } = 144$

Question

Write the standard form of the equation of the circle.
-Center (5, 7), r = 12 
A) $( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 144$
B) $( \mathrm { x } + 5 ) ^ { 2 } + ( \mathrm { y } + 7 ) ^ { 2 } = 12$
C) $( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 12$
D) $( x + 5 ) ^ { 2 } + ( y + 7 ) ^ { 2 } = 144$

Quizplus · Accepted Answer

The standard form of the equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center of the circle and $r$ is the radius. Given the center $(5, 7)$ and radius $12$, the equation becomes $(x - 5)^2 + (y - 7)^2 = 12^2$, which simplifies to $(x - 5)^2 + (y - 7)^2 = 144$.

Write the Standard Form of the Equation of the Circle (x−5)2+(y−7)2=144( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 144(x−5)2+(y−7)2=144

Write the Standard Form of the Equation of the Circle $( x - 5 ) ^ { 2 } + ( y - 7 ) ^ { 2 } = 144$