Convert the equation to the standard form for a hyperbola by completing the square.
-$$9 x ^ { 2 } - 4 y ^ { 2 } - 36 x - 8 y - 4 = 0$$
A) $\frac { ( x - 2 ) ^ { 2 } } { 9 } - \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$
B) $\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 9 } = 1$
C) $\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y + 1 ) ^ { 2 } } { 9 } = 1$
D) $\frac { ( x + 2 ) ^ { 2 } } { 4 } - \frac { ( y + 1 ) ^ { 2 } } { 9 } = 1$

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The Answer of Convert the equation to the standard form for a hyperbola by completing the square.
-$$9 x ^ { 2 } - 4 y ^ { 2 } - 36 x - 8 y - 4 = 0$$
A) $\frac { ( x - 2 ) ^ { 2 } } { 9 } - \frac { ( y + 1 ) ^ { 2 } } { 4 } = 1$
B) $\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y - 1 ) ^ { 2 } } { 9 } = 1$
C) $\frac { ( x - 2 ) ^ { 2 } } { 4 } - \frac { ( y + 1 ) ^ { 2 } } { 9 } = 1$
D) $\frac { ( x + 2 ) ^ { 2 } } { 4 } - \frac { ( y + 1 ) ^ { 2 } } { 9 } = 1$

Convert the Equation to the Standard Form for a Hyperbola 9x2−4y2−36x−8y−4=09 x ^ { 2 } - 4 y ^ { 2 } - 36 x - 8 y - 4 = 09x2−4y2−36x−8y−4=0

Convert the Equation to the Standard Form for a Hyperbola $9 x ^ { 2 } - 4 y ^ { 2 } - 36 x - 8 y - 4 = 0$