Find the Center, Transverse Axis, Vertices, Foci, and Asymptotes of the Hyperbola

Find the center, transverse axis, vertices, foci, and asymptotes of the hyperbola.
- $x ^ { 2 } - 16 y ^ { 2 } - 8 x - 64 y - 64 = 0$

A) center at $( - 2,4 )$
transverse axis is parallel to $x$ -axis
vertices at $( - 6,4 )$ and $( 2,4 )$
foci at $( - 2 - \sqrt { 17 } , 4 )$ and $( - 2 + \sqrt { 17 } , 4 )$
asymptotes of $y - 4 = - \frac { 1 } { 4 } ( x + 2 )$ and $y - 4 = \frac { 1 } { 4 } ( x + 2 )$
B) center at $( 4 , - 2 )$
transverse axis is parallel to $x$ -axis
vertices at $( 0 , - 2 )$ and $( 8 , - 2 )$
foci at $( 4 - \sqrt { 17 } , - 2 )$ and $( 4 + \sqrt { 17 } , - 2 )$
asymptotes of $y + 2 = - \frac { 1 } { 4 } ( x - 4 )$ and $y + 2 = \frac { 1 } { 4 } ( x - 4 )$
C) center at $( 4 , - 2 )$
transverse axis is parallel to $x$ -axis
vertices at $( 3 , - 2 )$ and $( 5 , - 2 )$
foci at $( 4 - \sqrt { 17 } , - 2 )$ and $( 4 + \sqrt { 17 } , - 2 )$
asymptotes of $y + 2 = - 4 ( x - 4 )$ and $y + 2 = 4 ( x - 4 )$
D) center at $( 4 , - 2 )$
transverse axis is parallel to $\mathrm { y }$ -axis
vertices at $( 4 , - 6 )$ and $( 4,2 )$
foci at $( 4 , - 2 - \sqrt { 17 } )$ and $( 4 , - 2 + \sqrt { 17 } )$
asymptotes of $y - 2 = - 4 ( x + 4 )$ and $y - 2 = 4 ( x + 4 )$